Hasi pemfaktoran dari x2-6x+3

x²-6x+3

x1.x2 = -b±√b²-4ac/2a
= -(-6)±√-6²-4.1.3/2.1
= 6±√36-12/2
= 6±√24/2

x1 = 6+√24/2
= 6+4,9/2
= 10,9/2
= 109/10/2
= 218/10
= 21,8

x2 = 6-√24/2
= 6-4,9/2
= 2,9/2
= 29/10/2
= 58/10
= 5,8