harga 3 baju dan 2 kaos adalah 280.000 sedangkan harga 1 baju dan 3kaos adalah 210.000 harga enam baju dan lima kaos adalah

3b + 2k = 280.000 | × 3
b + 3k = 210.000 | × 2.

9b + 6k = 840.000.
2b + 6k = 420.000.
______________ -
7b = 420.000.
b = 420.000/7.
b = 60.000.

b + 3k = 210.000.
3k = 210.000 - b.
3k = 210.000 - 60.000.
3k = 150.000.
k = 150.000/3.
k = 50.000.

= 6b + 5k.
= 6(60.000) + 5(50.000).
= 360.000 + 250.000.
= Rp610.000,00.

3b+1k = 280.000. (×3)
1b+3k =210.000. (×1)
eliminasikan ..
9b+3k = 840.000
1b+3k =210.000
8b=630.000
b=630.000:8
=78.750
subsitusikan kesalah satunya
1b+3k = 210.000
1(78.750)+3k =210.000
3k= 210.000-78.750
3k=31.250
k=31.250:3
=14.166

6b+5k
6(78.750)+5(14.166)
472.500+70.830
543.330