persamaan bayangan garis x-4y+3 = 0 oleh dilatasi pusat O dan faktor skala 2 dilanjutkan oleh pencerminan terhadap sumbu x adalah

dilatasi dengan faktor skala 2
[tex] \left[\begin{array}{ccc}x'\\y'\end{array}\right] [/tex] = [tex] \left[\begin{array}{ccc}x\\y\end{array}\right] [/tex] [tex] \left[\begin{array}{ccc}2&0\\0&2\end{array}\right] [/tex]
[tex] \left[\begin{array}{ccc}x'\\y'\end{array}\right] [/tex] = [tex] \left[\begin{array}{ccc}2x\\2y\end{array}\right] [/tex]

dirotasi terhadap sumbu X
[tex] \left[\begin{array}{ccc}x''\\y''\end{array}\right] [/tex] = [tex] \left[\begin{array}{ccc}2x\\2y\end{array}\right] [/tex] [tex] \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] [/tex]
[tex] \left[\begin{array}{ccc}x'\\y'\end{array}\right] [/tex] = [tex] \left[\begin{array}{ccc}2x\\-2y\end{array}\right] [/tex]

x''=2x
x=x''/2.....1

y''=-2y
y= -y''/2

=x(\frac{1}{2}) - 4y(-\frac{1}{2}) + 3
=\frac{x}{2} +2y +3
=x+4y+6