fungsi y= x3-3x2+3x-2 mempunyai nilai stationer

y = x^3 - 3x^2 + 3x - 2
Syarat stasioner:
y' = 0
3x^2 - 6x + 3 = 0
------------------------ (bagi 3)
x^2 - 2x + 1 = 0
(x - 1)(x - 1) = 0
x = 1
y = (1)^3 - 3(1)^2 + 3(1) - 2
= 1 - 3 + 3 - 2
= -1
(1, -1)