tolong bantu diselesaikan kk

s(t) = t^3 - 6t^2 + 9t + 4
v(t) = 3t^2 - 12t + 9
a(t) = 6t - 12

(1) v = 0
3t^2 - 12t + 9 = 0
------------------------ (÷ 3)
t^2 - 4t + 3 = 0
(t - 1)(t - 3)
t = 1 ; t = 3

t = 1
s(1) = 8
a(1) = -6

t = 3
s(3) = 4
a(3) = 6

(2) a = 0
6t - 12 = 0
6t = 12
t = 2

s(2) = 6
v(2) = -2