Fisika

Pertanyaan

luas a=5cm2,luas b=10cm2,Fb=400N,ditanya=tekanan pada A adalah...N/cm²

2 Jawaban

  • P = F/A

    Pa = Pb
    Fa/LA = Fb/Lb
    Fa/5 = 400/10
    Fa = 40×5
    Fa = 200 N

    Pa = 200/5
    Pa = 40 N/cm^2

    atau bisa dgn cara

    Pb = Fb/Lb
    Pb = 400/10
    Pb = 40

    Pa = Pb
    Pa = 40N/m^2
  • Dik: Aa= 5cm^2
    Ab= 10 cm^2
    Fb= 400 N
    Dit:pa =...
    Jawab:
    Fa/Aa=Fb/Ab
    Fa/5= 400/10
    Fa=400/10×5
    Fa=200N
    Tekanan dia A= Fa/Aa
    =200/5 =40...
    Atau :
    pa=pb
    pa=Fb/Ab
    pa=400/10
    pa=40 N/cm

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