Matematika

Pertanyaan

Nilai dari (2log8+2log3.^3log4/3log2-3log18)2

2 Jawaban

  • ²log 8 = 3
    ²log 3.³log 4 = ²log 4 = 2
    ³log 2 - ³log 18 = ³log (2/18) = ³log 1/9 = -2
    jadi
    {(3 + 2)/-2}²
    = (5 / -2)²
    = 25 / 4
  • penyelesaian
    ((2log8 + 2log3 x 3log4) / (3log2 - 3log18))²
    = (2log2³ + 2log4) / (3log2 - 3log18))²
    = (2log2³ + 2log2²) / (3log(2/18)))²
    = ((3 + 2) / 3log(1/9))²
    = ((3 + 2) / 3log(1/3²))²
    = ((3 + 2) / 3log3⁻²)²
    = ((3 + 2) / -2)²
    = (5 / -2)²
    = 25 / 4

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