Nilai dari (2log8+2log3.^3log4/3log2-3log18)2
Matematika
MFaisalAzuma
Pertanyaan
Nilai dari (2log8+2log3.^3log4/3log2-3log18)2
2 Jawaban
-
1. Jawaban bapakdr
²log 8 = 3
²log 3.³log 4 = ²log 4 = 2
³log 2 - ³log 18 = ³log (2/18) = ³log 1/9 = -2
jadi
{(3 + 2)/-2}²
= (5 / -2)²
= 25 / 4 -
2. Jawaban andhikahanif
penyelesaian
((2log8 + 2log3 x 3log4) / (3log2 - 3log18))²
= (2log2³ + 2log4) / (3log2 - 3log18))²
= (2log2³ + 2log2²) / (3log(2/18)))²
= ((3 + 2) / 3log(1/9))²
= ((3 + 2) / 3log(1/3²))²
= ((3 + 2) / 3log3⁻²)²
= ((3 + 2) / -2)²
= (5 / -2)²
= 25 / 4