Matematika

Pertanyaan

sederhanakan
a.2/3 x 2log64-1/2 x 2log16
b.alog2x+3(alog x-alog y)

2 Jawaban

  • a. 2/3 x 6 - 1/2 x 4 = 4-2 =2
    b. alog2x + alog[x^{3} [/tex]/[ y^{3} [/tex]
        alog2x X [x^{3} [/tex]/[ y^{3} [/tex]
        alog 2[x^{4} [/tex]/[ y^{3} [/tex]
  • 2/3 x 2log 64 - 1/2 x 2log 16
    = 2/3 x 2log 2pangkat 6 - 1/2 x 2log 2pangkat 4
    =2/3 x 6 - 1/2 x 4
    =12/3 - 4/2
    =4-2
    =2

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