diketahui sistem persamaan 3x+7y=1dan2x-3y=16.tentukan nilai xy

3x + 7y = 1 (x2) 6x + 14y = 2
2x - 3y = 16 (x3) 6x - 9y = 48

eliminasi x
14y - (-9y) = 2- 48
14y + 9 y = - 46
23 y = - 46
y = (-46) / 23 = -2

subtitusi y
2x - 3y = 16
2x - 3(-2) = 16
2x - (-6) = 16
2x + 6 = 16
2x = 16 -6 = 10
x = 10/2 = 5

x. y = 5 . (-2) = -10