Persamaan yg melalui titik (-2,5) dan tegak lurus dengan garis 3y-4x=12 adalah

3y-4x = 12
3y = 12 +4x
y = 12/3 + 4x/3
m = 4/3
tegak lurus = m1.m2 = -1
4/3 .m2 = -1
m2 = -3/4

y-y1 = m(x-x1)
y-5 = -3/4 (x-(-2))
y-5 = -3/4 (x+2)
4(y-5) = -3(x+2)
4y-20 = -3x -6
4y = -3x -6 + 20
4y = -3x + 14

4y +3x = 14
4y + 3x -14 = 0

-3x + 14 = 4y
-3x - 4y = - 14
-3x - 4y + 14 = 0