jika x>0 dan y>0, maka nilai (9-log2 x3 y3)/(1+2logx2y-logx5 y3 )
Matematika
armitanur1
Pertanyaan
jika x>0 dan y>0, maka nilai (9-log2 x3 y3)/(1+2logx2y-logx5 y3 )
1 Jawaban
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1. Jawaban Cadilac
(3-logx^3y^3)(3+logx^3y^3)/
(6+logx^24y^12-6logx^30y^18)
= (3-3logx^3y^3)(3+3logx^3y^3)/
(6-logx^6y^6)
= (3(1-logxy))(3(1+logxy))/(6-6logxy)
= (3(1-logxy))(3(1+logxy))/(6(1-logxy)
= 1/2 (3(1+logxy)
= 3/2 (log10xy)