Diketahui segitiga ABC dengan AB=44cm,BC=37cm,dan AC=15cm.panjang jari -jari lingkaran luar segitiga ABC adalah....

S = 1/2 K
S = 1/2 (44 + 37 + 15)
S = 1/2 (96)
S = 48

L = √{s (s - a)(s - b)(s - c)
L = √48 (48 - 44)(48 - 37)(48 - 15)
L = √48 (4) (11) (33)
L = √ (16) (3) (4) (11) (11) (3)
L = 4 x 3 x 2 x 11
L = 264

r = a.b.c / 4L
r = 44 . 37 . 15 / 4 (264)
r = 24.420 / 1056
r = 23,125 cm