diketahui f(x)=2x tambah 1 dan (f°g)(x)=4x² tambah 6x tambah 3. nilai g(2) = ? tlong dngn caranya, terimaksih

f(x) = 2x + 1
(fog)(x) = 4x² + 6x + 3

f(g(x)) = 4x² + 6x + 3
2g(x) + 1 = 4x² + 6x + 3
2g(x) = 4x² + 6x + 2
g(x) = (4x² + 6x + 2)/2
g(x) = 2x² + 3x + 1

g(2) = 2(2)² + 3(2) + 1
        = 8 + 6 + 1
        = 15