Matematika

Pertanyaan

hitunglah deret ini 7+10+13+16....+500 =

2 Jawaban

  • a = 7
    b = 3
    Un = 500

    a + (n-1)b = Un
    7 + (n-1)3 = 500
    7 + 3n -3 = 500
    3n = 496
    n = 496 / 3

    Sn = n /2 (a + Un)
    Sn = 496/3/2 (7+500)
    Sn = 496 / 6 (507)
    Sn = 41912

  • langsung aja y

    a = 7
    b = 10-7 = 3

    Un = a + (n-1)b
    500 = 7 + (n-1)3
    500 = 7 + 3n - 3
    3n = 500 - 4
    3n = 496
    n = 496/3

    S496/3 = 496/3 : 2 (a + Un)
    S496/3 = 496/6 (7+500)
    S496/3 = 496/6 (507)
    S496/3 = 41.912

    semoga berguna +_+

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