Matematika

Pertanyaan

p log(2x-1).5logp=2, ditanya x ?

2 Jawaban

  • ^plog(2x-1).^5logp = 2
    ^5logp.^plog(2x-1)=2
    ^5log(2x-1)=2
    ^5log(2x-1)= ^5log5²
    2x-1=5²
    2x=25+1
    2x=26
    x=26/2
    x=13
  • plog(2x - 1) . 5logp = 2
    5logp . plog(2x - 1) = 2
    5log(2x - 1) = 5log5^2
    (2x - 1) = 5^2
    2x = 25 + 1
    x = 26/2 = 13

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