a= 9log akar pangkat tiga dari 16, b = 2 log 1/3 dit :a.b

Dik:
a = ⁹log∛16
b = ²log1/3

Dit:
a.b = ........................... ?

Jwb:
a = ⁹log∛16
a = 2.³log2^4/3
a = 4/6.³log2

b = ²log1/3
b = ²log3^-1
b = -1.²log3

Jadi,
a . b
= 4/6.³log2 . -1.²log3
= (4/6)(-1).³log2 . ²log3
= -4/6.³log3
= -4/6.1
= -4/6
= -2/3