perbandingan panjang sisi sisi segitiga ABC yaitu a:b:c=5:3:4.jika keliling 84cm,maka panjang sisi AB=

a:b:c = 5:3:4
keliling = s1 + s2 + s3
A = 5/12 . 84 = 5. 7 = 35 cm
B = 3/12 . 84 = 3. 7 = 21
C = 4/12 . 84 = 4. 7 = 28

AB = 35 + 21 = 56 cm

1) Mencari nilai perbandingan.
Keliling segitiga = a + b + c
84cm = 5x + 3x + 4x
84cm = 12x
x (nilai perbandingan) = 7cm

2) Sisi AB = 5x
= 5 . 7
= 35cm

Maafk kalau salah.