Suatu fungsi dirumuskan f(x)=ax+b. Jika f(2)=3 dan f(-3)=13, maka nilai=a+b adalah...

f(x)=ax+b
f(2)=3
f(-3)=13
______-
5. =-10
a=-2

f(2)=-2x2+b=3
=-4+b=3
b=3+4
b=7
nilai a+b=-2+7=5
SEMOGA BERMANFAAT!!!

f(x)=ax+b.
Jika f(2)=3
f(-3)=13, a+b = ?
Jawab
.
> f(x) = ax+b, jika f(2) = 3
f(2) = a(2)+b
3 = 2a+b
> f(x) = ax+b, jika f(-3) = 13
f(-3) = a(-3)+b
13 = -3a+b
> nyari a
3 = 2a+b
13 = -3a+b
______-
-10 = 5a
-2 = a
> nyari b (masukan a = -2 ke salah satu persamaan, ane pakenya yang pertama)
3 = 2a+b
3 = 2.-2 +b
3 = -4+b
3+4 = b
7 = b
> a+b = -2 + 7
a+b = 5