jika ³log6 = x, dan ³log 7 = y maka 6log21 adalah ...

6 log21
= 6 log(7*3)
= 6 log7 + 6 log3
= 6 log3 * ³log7 + 6 log3
= 1/³log6 * y + 1/³log6
= y/x + x
= x²+y / x

semoga membantu :)

3log6 = x, 3log7 = y

6log21 = (3log21)/(3log6)
= (3log3.7)/(3log6)
= (3log3 + 3log7)/(3log6)
= (1 + y)/x