2 5log4+5log25+5log10-5log32

2⁵log4 + ⁵log25 + ⁵log10 - ⁵log32
= ⁵log4² + ⁵log25 + ⁵log10 - ⁵log32
= ⁵log16 + ⁵log25 + ⁵log10 - ⁵log32 
= ⁵log(16.25) + ⁵log10 - ⁵log32
= ⁵log400 + ⁵log10 - ⁵log32
= ⁵log(400.10) - ⁵log32
= ⁵log4000 - ⁵log32
= ⁵log(4000/32)
= ⁵log125
= ⁵log5³
= 3.⁵log5
= 3.1
= 3

logaritma

2. ⁵log 4 + ⁵log 25 + ⁵log 10 - ⁵log 32 =
= ⁵log [ (4² x 25 x 10)/(32)]
= ⁵log [4.000 /32]
= ⁵log 125
= ⁵log 5³
 = 3. (⁵log 5)
= 3 (1)
= 3