tolong dibantu ya. itu sudah ada jawabannya, tinggal caranya aja gimana. besok dikumpul mohon dibantu yaa :)

1) Lim (x^2 + 3x + 2)/(x^2 + 4x + 3) => diralat bukan (x^2 + 4x + 2)
= Lim (x + 2)(x + 1)/(x + 3)(x + 1)
= Lim (x + 2)/(x + 3)
= (-1 + 2)/(-1 + 3)
= 1/2

2) Lim ((x + h)^3 - x^3) / h
= Lim ((x^3 + 3x^2.h + 3xh^2 + h^3) - x^3) / h
= Lim (3x^2h + 3xh^2 + h^3)/h
= Lim h(3x^2 + 3xh + h^2)/h
= Lim (3x^2 + 3xh + h^2)
= 3x^2 + 3x(0) + 0^2
= 3x^2

3) Lim (4 - x^2)/(3 - √(x^2 + 5) . (3 + √(x^2 + 5))/(3 + √(x^2 + 5))
= Lim (4 - x^2)(3 + √(x^2 + 5))/(9 - (x^2 + 5))
= Lim (4 - x^2)(3 + √(x^2 + 5))/(4 - x^2)
= Lim (3 + √(x^2 + 5)
= 3 + √(2^2 + 5)
= 3 + √9
= 6

Pake Turunan aja ya.

 1. 2x + 3 / 2x + 4 => 2(-1) + 3 / 2(-1) + 4
= 1 / 2
2. x^3 + 3x^2h + 3xh^2 + h^3 - x^3/ h
= 3x^2h + 3xh^2 + h^3/h
= h ( 3x^2 + 3xh + h^2)/h
= 3x^2 + 3xh + h^2
h -> 0 = 3x^2 + 0 + 0 = 3x^2

3. Pake turunan
  0 - 2x / -1/2 (2x)(x^2+5)^-1/2
-2x / -x((x^2+5)^-1/2
x -> 2

-4 / -2(9^-1/2)
=2/(1/3)
= 6